x^2+128x-129=0

Solution for x^2+128x-129=0 equation:

Simplifying
x2 + 128x + -129 = 0

Reorder the terms:
-129 + 128x + x2 = 0

Solving
-129 + 128x + x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(-129 + -1x)(1 + -1x) = 0

Subproblem 1
Set the factor '(-129 + -1x)' equal to zero and attempt to solve:

Simplifying
-129 + -1x = 0

Solving
-129 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '129' to each side of the equation.
-129 + 129 + -1x = 0 + 129

Combine like terms: -129 + 129 = 0
0 + -1x = 0 + 129
-1x = 0 + 129

Combine like terms: 0 + 129 = 129
-1x = 129

Divide each side by '-1'.
x = -129

Simplifying
x = -129
Subproblem 2
Set the factor '(1 + -1x)' equal to zero and attempt to solve:

Simplifying
1 + -1x = 0

Solving
1 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1x = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1x = 0 + -1
-1x = 0 + -1

Combine like terms: 0 + -1 = -1
-1x = -1

Divide each side by '-1'.
x = 1

Simplifying
x = 1
Solution
x = {-129, 1}